magnitude of the net displacement

| January 29, 2015

Rock faults are ruptures along which opposite faces of have slid past each other. In Fig. 3-36, points .4 and B coincided before the rock in the foreground slid down to the right. The net displacement B is  width=long the plane of the fault. The horizontal component of  width= is the strike-slip AC. The component of  width= that is directed down the plane of the fault is the dip-slip AD. (a) What is the magnitude of the net displacement  width= if the strike-slip is 22.0 m and the dip-slip is 17.0 m? (b) If the plane of the fault is inclined at angle ? = 52.0° to the horizontal, what is the vertical component of width= ?

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2018DISC
displacement
magnitude and direction

Category: Coursework

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