Electrons

| January 25, 2015

Figure 22-38 shows a proton (p) on the central axis through a disk with a uniform charge density due to excess electrons. Three of those electrons are shown: electron e, at the disk center and electrons ec at opposite sides of the disk, at radius R from the center. The proton is initially at distance z = R = 2.00 cm from the disk. At that location, what are the magnitudes of (a) the electric field  width= due to electron e, and (b) the net electric field  width= due to electrons es? The proton is then moved to z = R/10.0. What then are the magnitudes of (c)  width= and (d)  width= at the proton”s location? (e) From (a) an (c) we see that as the proton gets nearer to the disk, the magnitude of  width=  increases. Why does the magnitude of  width= decrease, as we see from (b) and (d)?

 width=

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2018DISC
Magnitude
Dipoled electric field

Category: Coursework

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