Electric fields

| January 25, 2015

In Fig. 22-44, a thin glass rod forms a semicircle of radius r = 5.00 cm. Charge is uniformly distributed along the rod, with +q = 4.50 pC in the upper half and -q = – 4.50 pC in the lower half. What are the (a) magnitude and (b) direction (relative to the positive direction of the x axis) of the electric field  width= at P, the center of the semicircle?

 width=

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Dipoled electric field
Electric fields

Category: Coursework

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